Jennie

分块，对于每一个块，排个序

就可以了

#include<cstdio>
#include<iostream>
#include<cstring>
#include<iomanip>
#include<cmath>
#include<stack>
#include<algorithm>
#define int long long
using namespace std;
template<class T>inline void read(T &x)
{
    x=0;register char c=getchar();register bool f=0;
    while(!isdigit(c))f^=c=='-',c=getchar();
    while(isdigit(c))x=(x<<3)+(x<<1)+(c^48),c=getchar();
    if(f)x=-x;
}
template<class T>inline void print(T x)
{
    if(x<0)putchar('-'),x=-x;
    if(x>9)print(x/10);
    putchar('0'+x%10);
}
int n;
int a[5000001];
int tem[5000001];
int l[5000001];
int r[5000001];
int be[500001];
int cop[5000001];
int len;
int num;
int f;
int x,y,z;
int tag[5000001];
void reini(int x){
    for(int i=l[x];i<=r[x];++i){
        cop[i]=a[i]+tag[x];
        a[i]+=tag[x];
    }
    tag[x]=0;
    sort(cop+l[x],cop+r[x]+1);
}
void add(int ll,int rr,int k){
    if(be[ll]==be[rr]){
        for(int i=ll;i<=rr;++i){
            a[i]+=k;
        }
        reini(be[ll]);
    }else{
        for(int i=ll;i<=r[be[ll]];++i){
            a[i]+=k;
        }
        reini(be[ll]);
        for(int i=be[ll]+1;i<be[rr];++i){
            tag[i]+=k;
        }
        for(int i=l[be[rr]];i<=rr;++i){
            a[i]+=k;
        }
        reini(be[rr]);
    }
}
int que(int ll,int rr,int k){
    int ans=0;
    if(be[ll]==be[rr]){
        for(int i=ll;i<=rr;++i){
            if(a[i]+tag[be[ll]]<k)
            ans++;
        }
        return ans;
    }else{
        for(int i=ll;i<=r[be[ll]];++i){
            if(a[i]+tag[be[ll]]<k)
            ans++;
        }
        for(int i=l[be[rr]];i<=rr;++i){
            if(a[i]+tag[be[rr]]<k)
            ans++;
        }
        for(int i=be[ll]+1;i<be[rr];++i){
            ans+=lower_bound(cop+l[i],cop+r[i]+1,k-tag[i])-cop-l[i];
        }
        return ans;
    }
    return ans;
}
signed main(){
    read(n);
    for(int i=1;i<=n;++i){
        read(a[i]);
    }
    int len=sqrt(n);
    num=n/len;
    if(n%len) num++;
    for(int i=1;i<=n;++i){
        be[i]=(i-1)/len+1;
    }
    for(int i=1;i<=num;++i){
        l[i]=(i-1)*len+1;
        r[i]=(i)*len;
    }
    r[num]=n;
    for(int i=1;i<=num;++i){
        reini(i);
    }
    for(int i=1;i<=n;++i){
        read(f);
        if(f==0){
            read(x);read(y);read(z);
            add(x,y,z);
        }else{
            read(x);read(y);read(z);
            printf("%lldn",que(x,y,z*z));
        }
    }
    return 0;
}